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n^2=64/121
We move all terms to the left:
n^2-(64/121)=0
We add all the numbers together, and all the variables
n^2-(+64/121)=0
We get rid of parentheses
n^2-64/121=0
We multiply all the terms by the denominator
n^2*121-64=0
Wy multiply elements
121n^2-64=0
a = 121; b = 0; c = -64;
Δ = b2-4ac
Δ = 02-4·121·(-64)
Δ = 30976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{30976}=176$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-176}{2*121}=\frac{-176}{242} =-8/11 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+176}{2*121}=\frac{176}{242} =8/11 $
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